Summary: The Postgres max() aggregate function returns the largest value from a column or expression across a set of rows, working with numeric, date, and timestamp types while ignoring NULL values. Use max() when you need the highest price, latest timestamp, or biggest transaction in a table, including grouped results with GROUP BY or conditional results with a FILTER clause. The function also operates as a window function for running maximums, and performance improves when the target column is indexed.

Find the maximum value in a set of values

You can use the Postgres max() function to find the maximum value in a set of values.

Use it for data analysis, reporting, and finding extreme values within datasets. You might use max() to find the product with the highest price in the catalog, the most recent timestamp in a log table, or the largest transaction amount in a financial system.

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The max() function has this simple form:

max(expression) -> same as expression

• expression: Any valid expression that can be evaluated across a set of rows. This can be a column name or a function that returns a value.

Consider an orders table that tracks orders placed by customers of an online store. It has columns order_id, customer_id, product_id, and order_date. We will use this table for examples throughout this guide.

CREATE TABLE orders (
    order_id SERIAL PRIMARY KEY,
    customer_id INTEGER NOT NULL,
    product_id INTEGER,
    order_amount DECIMAL(10, 2) NOT NULL,
    order_date TIMESTAMP NOT NULL
);

INSERT INTO orders (customer_id, product_id, order_amount, order_date)
VALUES
    (1, 101, 150.00, '2023-01-15 10:30:00'),
    (2, 102, 75.50, '2023-01-16 11:45:00'),
    (1, 103, 200.00, '2023-02-01 09:15:00'),
    (3, 104, 50.25, '2023-02-10 14:20:00'),
    (2, 105, 125.75, '2023-03-05 16:30:00'),
    (4, NULL, 90.00, '2023-03-10 13:00:00'),
    (1, 106, 180.50, '2023-04-02 11:10:00'),
    (3, 107, 60.25, '2023-04-15 10:45:00'),
    (5, 108, 110.00, '2023-05-01 15:20:00'),
    (2, 109, 95.75, '2023-05-20 12:30:00');

We can use max() to find the largest order amount:

SELECT max(order_amount) AS largest_order
FROM orders;

This query returns the following output:

 largest_order
---------------
        200.00
(1 row)

To find the most recent order date, we compute the maximum value of order_date:

SELECT max(order_date) AS latest_order_date
FROM orders;

This query returns the following output:

  latest_order_date
---------------------
 2023-05-20 12:30:00
(1 row)

You can use max() with GROUP BY to find the maximum values in each group:

SELECT customer_id, max(order_amount) AS largest_order
FROM orders
GROUP BY customer_id
ORDER BY largest_order DESC
LIMIT 5;

This query finds the largest order amount for each customer and returns the top 5 customers, sorted in order of the largest order amount.

 customer_id | largest_order
-------------+---------------
           1 |        200.00
           2 |        125.75
           5 |        110.00
           4 |         90.00
           3 |         60.25
(5 rows)

The FILTER clause allows you to selectively include rows in the max() calculation:

SELECT
    max(order_amount) AS max_overall,
    max(order_amount) FILTER (WHERE EXTRACT(MONTH FROM order_date) = 4) AS max_in_april
FROM orders;

This query calculates both the overall maximum order amount and the maximum order amount for the year 2023.

 max_overall | max_in_april
-------------+--------------
      200.00 |       180.50
(1 row)

To retrieve the entire row containing the maximum value, you can use a subquery:

SELECT *
FROM orders
WHERE order_amount = (SELECT max(order_amount) FROM orders);

This query returns the full details of the order with the maximum order_amount.

 order_id | customer_id | product_id | order_amount |     order_date
----------+-------------+------------+--------------+---------------------
        3 |           1 |        103 |       200.00 | 2023-02-01 09:15:00
(1 row)

max() can be used as a window function to calculate the running maximum over a set of rows:

SELECT
    order_id,
    order_date,
    max(order_amount) OVER (
        ORDER BY order_date
        ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW
    ) AS running_max_amount
FROM orders
ORDER BY order_date;

This query calculates the running maximum order amount over time, showing how the largest order amount changes as new orders come in.

 order_id |     order_date      | running_max_amount
----------+---------------------+--------------------
        1 | 2023-01-15 10:30:00 |             150.00
        2 | 2023-01-16 11:45:00 |             150.00
        3 | 2023-02-01 09:15:00 |             200.00
        4 | 2023-02-10 14:20:00 |             200.00
        5 | 2023-03-05 16:30:00 |             200.00
        6 | 2023-03-10 13:00:00 |             200.00
        7 | 2023-04-02 11:10:00 |             200.00
        8 | 2023-04-15 10:45:00 |             200.00
        9 | 2023-05-01 15:20:00 |             200.00
       10 | 2023-05-20 12:30:00 |             200.00
(10 rows)

max() ignores NULL values in its calculations. If all values in the set are NULL, max() returns NULL.

When used with an index on the column being evaluated, max() is typically very efficient. The database can often use an index scan to quickly find the maximum value without needing to examine every row in the table. For large datasets, ensure that the column used in the max() function is properly indexed to maintain good performance.

• min(): Returns the minimum value in a set of values.
• greatest(): Returns the largest value from a list of values/expressions within a single row.

• PostgreSQL documentation: Aggregate Functions

• array_agg
• avg
• count
• sum

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